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You might see “162 + 163 + 164 + 165 + 166 = ?” on a math quiz, or hear “Bet you can’t add up the five numbers from 162 through 166” from a friend who likes to boast about their math skills. But guess what — you can do it, and quickly! There are some simple math tricks that make adding up any 5 consecutive numbers easy. You can use them to wow your friends or impress your math teacher!
Steps
Method 1
Method 1 of 3:Multiplying the Middle Number by 5
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1Identify the middle number in the series. Let’s say you’re given the numbers 51, 52, 53, 54, and 55. 53 is the middle number in this case, since it has two numbers before and after it in the series.^{[1] X Research source }

2Multiply the middle number by 5 in your head. This is easier if you’re given small numbers like 1 through 5, of course (since 3 x 5 = 15). But it’s not that much more difficult to mentally multiply 53 x 5 = 265.^{[2] X Research source }
 First, separate 53 into 50 and 3.
 Second, multiply 50 x 5 = 250.
 Then, multiply 3 x 5 = 15.
 Finally, add those two results together: 250 + 15 = 265.
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3Confirm that your result ends in 5 or 0. The sum of any 5 consecutive whole numbers will always be divisible by 5, which means it will end in either 5 or 0. So, if your mental math gave you a result of 264 or 266, you know you need to recalculate.^{[3] X Research source }

4Try it with larger numbers or negative numbers too. For instance, say your consecutive numbers run from 1,263 through 1,267. To mentally multiply the middle number, 1,265, you could add up 5,000 (= 1,000 x 5), 1,000 (= 200 x 5), 300 (= 60 x 5), and 25 (= 5 x 5) to get 6,325 as the sum of 1,263 through 1,267.^{[4] X Research source }
 Or, let’s say that your given series is 3, 2, 1, 0, 1. You still multiply the middle number by 5 to get your result — in this case, 1 x 5 = 5, which is also the sum of (3) + (2) + (1) + 0 + 1.

5Grab a pencil and paper to see how it works. You can figure out the sum of any series of consecutive whole numbers by using the following formula, in which x = the sum, a = the first number in the series (e.g., 51), and n = the last number in the series (e.g, 55):^{[5] X Research source }
 x = (n x ((n + 1) / 2))  ((a  1) x (a / 2))
 x = (55 x (56 / 2))  (50 x 25.5)
 x = (55 x 28)  1275
 x = 1540  1275
 x = 265 (and 265 / 5 = 53, the middle number)
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Method 2
Method 2 of 3:Using the Highest or Lowest Number in the Series
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1Pick any 5 consecutive numbers. For a simpler example (Example A), try 11, 12, 13, 14, 15.
 For more of a challenge (Example B), try 232, 233, 234, 235, 236.

2Multiply the highest number by 5. For Example A, 15 x 5 = 75. For Example B, 236 x 5 = 1,180.

3Subtract 10 from your result to get the sum of the series. For Example A, 75  10 = 65. For Example B, 1,180  10 = 1,170.

4Use the lowest number instead by multiplying by 5 and adding 10. For Example A, (11 x 5) + 10 = 55 + 10 = 65. For Example B, (232 x 5) + 10 = 1,160 + 10 = 1,170. As you can see, you end up with the same results.

5Compare your result to multiplying the middle number by 5. In Example A, 13 is the middle number, and 13 x 5 = 65. In Example B, 234 is the middle number, and 234 x 5 = 1,170. To do Example B in your head, remember that you can break it up: (200 x 5 = 1,000) + (30 x 5 = 150) + (4 x 5 = 20) = 1,000 + 150 + 20 = 1,170.^{[6] X Research source }

6Use the formula to further confirm your result. Use x = (n x ((n + 1) / 2))  ((a  1) x (a / 2)), where x = the sum, n = the highest number, and a = the lowest number.^{[7] X Research source }
 For Example A:
 x = (15 x (16 / 2))  (10 x 5.5)
 x = (15 x 8)  55
 x = 120  55 = 65
 For Example B:
 x = (236 x (237 / 2))  (231 x 116)
 x = (236 x 118.5)  26796
 x = 27966  26796 = 1170
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Method 3
Method 3 of 3:Adding Up Other Amounts of Consecutive Numbers
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1Add four consecutive numbers by multiplying the highest by 4 and subtracting 6. For example, try 11, 12, 13, 14; 14 x 4 = 56, and 56  6 = 50.
 Or, you can multiply the sum of the middle two numbers by two. In the above case, 12 + 13 = 25, and 25 x 2 = 50.^{[8] X Research source }

2Add six consecutive numbers by multiplying the highest by 6 and subtracting 15. Say you have a consecutive series from 11 through 16. You’d multiply 16 x 6 = 96, then subtract 15 to get 81.
 Alternatively, you can multiply the sum of the middle two numbers by 3. In the above case, 13 + 14 = 27, and 27 x 3 = 81.^{[9] X Research source }

3Add seven consecutive numbers by multiplying the middle number by 7. If your series runs from 11 through 17, 14 is the middle number. Thus, 14 x 7 = 98.^{[10] X Research source }
 For any odd number (3, 5, 7, etc.) of consecutive numbers, you can always just multiply the middle number by the total number in the series.

4Add eight consecutive numbers by multiplying the highest by 8 and subtracting 28. If your numbers run from 11 through 18, multiply 18 x 8 = 144, then subtract 144  28 = 116.
 You can also multiply the sum of the middle two numbers by 4. In the above example, 14 + 15 = 29, and 29 x 4 = 116.^{[11] X Research source }
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Community Q&A

QuestionWhat are five consecutive whole numbers that add up to 50?DonaganTop AnswererLet n be the first number. Then (n) + (n+1) + (n+2) + (n+3) + (n+4) = 50. Combining terms, 5n + 10 = 50. Then 5n = 40, and n = 8. The numbers are 8, 9, 10, 11 and 12.

QuestionWhat are 5 consecutive whole numbers that equal 15?Community AnswerFirst divide 15 by 5 to get the middle number in the sequence. Since there are 5 numbers in the sequence used, we divide by 5. This gives us the number three. We know that this is the middle number in the sequence, so there are an equal amount of numbers both above and below this. Therefore, the numbers must be 1,2,3,4,5. Those five numbers add up to 15 to confirm that this answer is correct.

QuestionThe sum of five consecutive numbers is 100. How do I find the first number?DonaganTop AnswererLet n be the first number. Then the next four numbers will be n+1, n+2, n+3, and n+4. Add the five numbers together and set them equal to 100: (n) + (n+1) + (n+2) + (n+3) +(n+4) = 100. Add together the five terms on the left to get 5n + 10 and let that equal 100: 5n +10 = 100. Subtract 10 from both sides: 5n = 90. Divide both sides by 5: n = 18. That's the number you're looking for.

QuestionRhoda draws a number inside the box. If there are numbers 150 what is the possibility of getting 25?Community AnswerThe possibility of getting 25 would be one in 50. This sounds like a homework question; don't use wikiHow to do your homework for you. You can ask about concepts you don't understand, but not to answer your homework problems.

QuestionWhat are 5 consecutive whole numbers that equal 40?DonaganTop AnswererUsing Method 1 above, let 5n = 40, where n is the middle number of the five consecutive numbers. Solve for n, and go from there.

QuestionWhen 5 consecutive integers are added together and the sum is then multiplied by 5, the result is 225. What is the largest of the 5 consecutive integers?Community AnswerTo solve this, work backwards on the problem. The sum times 5 is equal to 225. 225 / 5 = 45, which is the sum we are trying to find. What are the 5 integers used to produce 45? They will have an average of 45 / 5, which is 9. 9 plus the 2 numbers on either side of it are 7, 8, 9, 10, 11, which equal 45 when added. Therefore, the largest of the 5 integers is 11.

QuestionFive consecutive numbers are 80. How do I find the numbers?DonaganTop AnswererFind the middle number by dividing 80 by 5. That's 16. Then the other four numbers are 14, 15, 17 and 18.

QuestionWhat are 5 consecutive even numbers used to make 80?Community Answer12 + 14 + 16 + 18 + 20. 80 / 5 = 16, so the required numbers are the two consecutive even numbers before 16, then 16, then the two consecutive even numbers after 16.

QuestionIf five consecutive integers multiplied is 120, what is the largest number?DonaganTop AnswererThe first five consecutive, positive integers (1, 2, 3, 4, and 5) multiply together to make 120. The largest of those integers is 5.

QuestionThe sum of five consecutive integers is 0. How do I solve?DonaganTop AnswererIf you're asking which five consecutive integers have a sum of zero, by inspection it's apparent that some of the integers would have to be negative and some positive in order to offset each other to the point that the sum is zero. Zero would have to be the middle number so that the other numbers will balance each other perfectly. Thus, the integers are 2, 1, 0, +1 and +2 (and yes, zero is an integer).
Tips
 You can add any sequence of consecutive numbers, even or odd, regardless of the number of integers the sequence contains, by adding the first and the last number in the sequence, dividing it by two and multiplying the answer by the number of integers in the sequence. In algebra, we can say ((a + b) / 2) x n, or rearrange it to (n x (a + b)) / 2 to remove a set of parenthesis.
 For instance, say your series is 10, 12, 14, 16, and 18. Plug the numbers into the formula to get x = 5 x (10 + 18) / 2; x = 5 x 28 / 2; x = 5 x 14; x = 70.
Thanks!
References
 ↑ http://www.mathonlymath.com/threeconsecutivenumbers.html
 ↑ http://www.mathonlymath.com/threeconsecutivenumbers.html
 ↑ https://nzmaths.co.nz/resource/consecutivenumbers
 ↑ http://www.mathonlymath.com/threeconsecutivenumbers.html
 ↑ https://betterexplained.com/articles/techniquesforaddingthenumbers1to100/
 ↑ http://www.mathonlymath.com/threeconsecutivenumbers.html
 ↑ https://betterexplained.com/articles/techniquesforaddingthenumbers1to100/
 ↑ http://www.mathonlymath.com/threeconsecutivenumbers.html
 ↑ http://www.mathonlymath.com/threeconsecutivenumbers.html
About This Article
To add 5 consecutive numbers quickly, start by identifying the middle number in the series. For example, if you were trying to add 1, 2, 3, 4, and 5, then 3 would be the middle number. Next, just multiply that number by 5 to get your answer! So in this example, you would multiply 3 by 5 and get 15, which is the same number you'd get if you were to add up 1, 2, 3, 4, and 5. To learn how to add 5 consecutive numbers quickly using the highest and lowest numbers in the series, scroll down!